NAME
stpcpy - copy a string returning a pointer to its end
SYNOPSIS
#define _GNU_SOURCE
#include <string.h>
char *stpcpy(char *dest, const char *src);
DESCRIPTION
The stpcpy() function copies the string pointed to by src (including
the terminating '\0' character) to the array pointed to by dest. The
strings may not overlap, and the destination string dest must be large
enough to receive the copy.
RETURN VALUE
stpcpy() returns a pointer to the end of the string dest (that is, the
address of the terminating null byte) rather than the beginning.
CONFORMING TO
This function is not part of the C or POSIX.1 standards, and is not
customary on Unix systems, but is not a GNU invention either. Perhaps
it comes from MS-DOS. Nowadays, it is also present on the BSDs.
EXAMPLE
For example, this program uses stpcpy() to concatenate foo and bar to
produce foobar, which it then prints.
#define _GNU_SOURCE
#include <string.h>
#include <stdio.h>
int
main(void)
{
char buffer[20];
char *to = buffer;
to = stpcpy(to, "foo");
to = stpcpy(to, "bar");
printf("%s\n", buffer);
}
BUGS
This function may overrun the buffer dest.
SEE ALSO
bcopy(3), memccpy(3), memcpy(3), memmove(3), strcpy(3), wcpcpy(3),
feature_test_macros(7)
COLOPHON
This page is part of release 3.24 of the Linux man-pages project. A
description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.